A geometric series has common ratio r, and an arithmetic series has
first term a and common difference d, where a and d are non-zero.
The first three terms of the geometric series are equal to the first, tenth and thirteenth terms
respectively of the arithmetic series.
(i)
Show that 81d2+6ad=0.
(ii)
The sum of the first n terms of the arithmetic series is denoted by S.
Given that a>0,
find the set of possible values of n for which S exceeds 4a.
(iii)
Deduce that the geometric series is convergent, and find, in terms of a, the sum to infinity.
Answer
(ii)
{n∈Z:5≤n≤23}.
(iii)
The geometric series is convergent because −1<r=31<1. S∞=23a.