Arithmetic and geometric progressions

Question code: 2934

Question 0404

A geometric series has common ratio r,{r,} and an arithmetic series has first term a{a} and common difference d,{d,} where a{a} and d{d} are non-zero. The first three terms of the geometric series are equal to the first, tenth and thirteenth terms respectively of the arithmetic series.

(i)

Show that 81d2+6ad=0.{81 d^2 + 6 ad = 0.}
[4]

(ii)

The sum of the first n{n} terms of the arithmetic series is denoted by S.{S.} Given that a>0,{a>0,} find the set of possible values of n{n} for which S{S} exceeds 4a.{4 a.}
[5]

(iii)

Deduce that the geometric series is convergent, and find, in terms of a,{a,} the sum to infinity.
[5]
Answer

(ii)

{nZ:5n23}.{\{ n \in \mathbb{Z}: 5 \leq n \leq 23 \}.}

(iii)

The geometric series is convergent because 1<r=13<1.{-1 < r = \frac{1}{3} < 1.}
S=32a.{S_\infty = \frac{3}{2} a.}
Question code: 2934