Differentiation and applications

Question code: bb3

Question 0605

A curve has parametric equations
x=sin2t,y=cos3t,for 0tπ2.x = \sin^2 t, \quad y = \cos^3 t, \quad \textrm{for } 0 \leq t \leq {\textstyle \frac{\pi}{2}}.

(i)

Sketch the curve
[2]

(ii)

The normal to the curve at the point (sin2θ,cos3θ),{( \sin^2 \theta, \cos^3 \theta ),} where 0<θ<12π,{0 < \theta < \frac{1}{2} \pi,} meets the x{x}- and y-axes {y \textrm{-axes }} at P{P} and Q{Q} respectively. The origin is denoted by O.{O.} Show that the area of triangle OPQ{OPQ} is
112cosθ3cos4θ2sin2θ2.\frac{1}{ 12 \cos \theta } \Big| 3 \cos^{4} \theta - 2 \sin^2 \theta \Big|^2.
[6]

(iii)

Show that the area under the curve for 0tπ2{0 \leq t \leq \frac{\pi}{2}} is 20π2sintcos4tdt,{\displaystyle 2 \int_0^{\frac{\pi}{2}} \sin t \cos^{4} t \, \mathrm{d} t,} and use the substitution u=cost{u = \cos t} to find this area.
[5]
Answer
25 units2.{\frac{2}{5} \textrm{ units}^2.}
Question code: bb3